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One among the lanthanoids, Ce (III) can be easily oxidised to Ce (IV). Explain. - Chemistry (Theory)

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प्रश्न

One among the lanthanoids, Ce (III) can be easily oxidised to Ce (IV). Explain.

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उत्तर

  1. Ce (III) has an electronic configuration [Xe] 4f1 and can lose one more electron to attain a stable noble gas-like configuration in Ce (IV).
  2. Ce (IV) has a stable electronic configuration similar to a noble gas, making Ce (III) easy to oxidize to Ce (IV).
  3. The Ce (IV) ion is a strong oxidizing agent and easily gets reduced to Ce (III), showing that Ce (III) easily oxidizes to Ce (IV).
  4. Unlike other lanthanoids, Ce can exist stably in +4 state due to the extra stability and energy factors related to its electronic configuration.
  5. This property is unique as most lanthanoids prefer the +3 oxidation state; the ability of Ce to attain the +4 state is why compounds like Ce(SO4)2 are commonly used in volumetric analysis.

Hence, Ce (III) can be easily oxidized to Ce (IV) due to the stability and favorable energy of the +4 state with noble gas configuration.

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अध्याय 8: d-and ƒ-Block Elements - REVIEW EXERCISES [पृष्ठ ४९२]

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नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
अध्याय 8 d-and ƒ-Block Elements
REVIEW EXERCISES | Q 8.52 | पृष्ठ ४९२
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