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प्रश्न
on treatment with Con. H2SO4 predominately gives
विकल्प
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उत्तर
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संबंधित प्रश्न
Carbolic acid is ____________.
One mole of an organic compound (A) with the formula C3H8O reacts completely with two moles of HI to form X and Y. When Y is boiled with aqueous alkali it forms Z. Z answers the iodoform test. The compound (A) is ___________.
0.44 g of a monohydric alcohol, when added to methyl magnesium iodide in ether, liberates at STP 112 cm3 of methane with PCC the same alcohol form a carbonyl compound that answers the silver mirror test. Identify the compound.
Complete the following reaction.
What will be the product (X and A) for the following reaction?
\[\ce{acetylchloride ->[i) CH3MgBr][ii) H3O^+] X ->[acid K2Cr2O7] A}\]
How will you convert acetylene into n-butyl alcohol?
Draw the major product formed when 1-ethoxyprop-1-ene is heated with one equivalent of HI.
Identify the product (s) is / are formed when 1 – methoxy propane is heated with excess HI. Name the mechanism involved in the reaction
Predict the major product, when 2-methyl but -2-ene is converted into an alcohol in each of the following method.
Acid catalysed hydration
What will be the product (X and A) for the following reaction
\[\ce{acetylchloride ->[i) CH3MgBr][ii) H3O^+ ]X ->[acid K2Cr2O7]A}\]
