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On Q, the Set of All Rational Numbers, * is Defined by a ∗ B = a − B 2 , Shown that * is No Associative ? - Mathematics

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प्रश्न

On Q, the set of all rational numbers, * is defined by \[a * b = \frac{a - b}{2}\] , shown that * is no associative ?

योग
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उत्तर

\[\text{Let }a, b, c \in Q . \text{Then}, \] 
\[a * \left( b * c \right) = a * \left( \frac{b - c}{2} \right)\] 
                   \[ = \frac{a - \left( \frac{b - c}{2} \right)}{2}\] 
                   \[ = \frac{2a - b + c}{4}\] 
\[\left( a * b \right) * c = \left( \frac{a - b}{2} \right) * c\] 
 \[ = \frac{\left( \frac{a - b}{2} \right) - c}{2}\] 

\[ = \frac{a - b - 2c}{4}\] 
\[\text{Thus, a} * \left( b * c \right) \neq \left( a * b \right) * c\] 
\[\text{If a} = 1, b = 2, c = 3 \] 
\[1 * \left( 2 * 3 \right) = 1 * \left( \frac{2 - 3}{2} \right)\] 
                  \[ = 1 * \frac{- 1}{2}\] 
                 \[ = \frac{1 + \frac{1}{2}}{2}\]

                  \[ = \frac{3}{4}\] 
\[\left( 1 * 2 \right) * 3 = \left( \frac{1 - 2}{2} \right) * 3\] 
                  \[ = \frac{- 1}{2} * 3\] 
                 \[ = \frac{\frac{- 1}{2} - 3}{2}\] 
                 \[ = \frac{- 7}{4}\] 
\[\text{Therefore}, \exists \text{ a} = 1, b = 2, c = 3 \in \text{R such that a} * \left( b * c \right) \neq \left( a * b \right) * c\]

Thus, * is not associative on Q.

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अध्याय 3: Binary Operations - Exercise 3.2 [पृष्ठ १२]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 3 Binary Operations
Exercise 3.2 | Q 9 | पृष्ठ १२

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