Question

Monica has a piece of Canvas whose area is 551 m2. She uses it to have a conical tent made, with a base radius of 7m. Assuming that all the stitching margins and wastage incurred while cutting, amounts to approximately 1 m2. Find the volume of the tent that can be made with it.

Answer 1

Given that, 

Area of canvas ` 551m^2` and area of the canvas lost in wastage is `1m^2` 

∴ area of canvas available for making the tent is `(551-1)m^2=550m^2.`

SA of tent =`550m^2` required base radius of conical tent= 7m 

CSA of tent=`550m^2  `

`pirl=550m^2` 

`⇒22/7xx7xxl=550` 

`⇒l=550/22=25m ` 

Now, WKT 

`l^2=r^2+h^2` 

`⇒(25)^2-(7)^2=h^2 ` 

`⇒ h=sqrt(625-49)` 

`=sqrt576=24m` 

So, the volume of the conical tent =`1/3pir^2h` 

`= 1/3xx3.14xx(7xx7)(24)m^3=1232m^3`