Question

\[\ce{MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2}\]

0.02 moles of pure MnO₂ is heated strongly with conc. HCl. Calculate mass of MnO₂ used.

Answer 1

MnO₂ = Mn + 2(O)

= 55 + 2(16)

= 55 + 32

= 87 g

1 mole of MnO₂ weighs = 87 g (mol. Mass)

So, 0.02 mole will weigh = 87 × 0.02 = 1.74 g