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प्रश्न
Match the statements in Column A with those in Column B.
| Column A | Column B |
|
1. A metal which reacts with cold water to from hydrogen. |
1. Reduction |
| 2. A gas which is inflammable and non-supporter of combustion | 2. Hydrogenation |
|
3. A process in which vanspati ghee is prepared from vegitable oils |
3. oxidation |
|
4. The removal ofhydrogen or addition of oxygen |
4. sodium |
| 5. The addition of hydrogen or removal of oxygen | 5. Hydrogen |
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उत्तर
| Column A | Column B |
|
1. A metal which reacts with cold water to from hydrogen. |
4. sodium |
| 2. A gas which is inflammable and non-supporter of combustion | 5. Hydrogen |
|
3. A process in which vanspati ghee is prepared from vegitable oils |
2. Hydragenation |
|
4. The removal hydrogen or addition of oxygen. |
3. oxidation |
| 5. The addition hydrogen or removal of oxygen | 1. Reduction |
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संबंधित प्रश्न
Hydrogen may be prepared in the laboratory by the action of a metal on an acid.
Which of the metals copper, zinc, magnesium or sodium would be the most suitable?
Hydrogen may be prepared in the laboratory by the action of a metal on an acid.
Which of the acids dilute sulphuric, concentrated sulphuric, dilute nitric acid and concentrated nitric acid would you choose? Explain why you would not use the acids you reject.
Give reason:
A candle brought near the mouth of a jar containing hydrogen gas starts burning but is extinguished when pushed inside the jar.
State how hydrogen occurs in the free state. Name three compounds containing hydrogen in the combined state.
Complete and balance the equation:
[General method]
Reactions of metals with dilute acids
Zinc - Zn + 2HCl → ______ + _______ [g]
How did the name ‘hydrogen’ originate? How does hydrogen occur in the combined state?
State the reactant added to hydrogen to obtain the respective product in following case.
Ammonia
Select the correct answer to the reactant added, to give the product in the preparation of hydrogen gas.
\[\ce{MgO + H2}\]
Give a balanced equation for the following conversion.
\[\ce{KAlO2<-KOH->K2ZnO2}\]
Give a balanced equation for the following conversion.
\[\ce{ZnO<-H2O->Fe3O4}\]
