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प्रश्न
`lim_(x rightarrow π/4) (8sqrt(2) - (cosx + sinx)^7)/(sqrt(2) - sqrt(2)sin2x)` is equal to ______.
विकल्प
14
7
`14sqrt(2)`
`7sqrt(2)`
MCQ
रिक्त स्थान भरें
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उत्तर
`lim_(x rightarrow π/4) (8sqrt(2) - (cosx + sinx)^7)/(sqrt(2) - sqrt(2)sin2x)` is equal to 14.
Explanation:
`lim_(x rightarrow π/4) (8sqrt(2) - (cosx + sinx)^7)/(sqrt(2) - sqrt(2)sin2x)` ...`["from" 0/0]`
∴ Apply L-hospital rule
`lim_(x rightarrow π/4) (-7(cosx + sinx)^6(cosx - sinx))/(-2sqrt(2)cos2x)` ...`["from" 0/0]`
`lim_(x rightarrow π/4) (7(cosx + sinx)^6(cosx - sinx))/(2sqrt(2)(cosx - sinx)(cosx + sinx))` ...[∵ cos2x = cos2x – sin2x]
`lim_(x rightarrow π/4) (7(cosx + sinx)^6)/(2sqrt(2)(cosx + sinx))`
= `(7(sqrt(2))^6)/(2sqrt(2)(sqrt(2))`
= `(7 xx 8)/4`
= 14
shaalaa.com
Limits Using L-hospital's Rule
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