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प्रश्न
Let y = `cot^-1((5x^2 + 1)/(4x)) + cot^-1((2x - 3)/(2 + 3x))`, then `dy/dx` = ______
विकल्प
`1/(1 + 25x^2)`
`5/(1 + 25x^2)`
`5/sqrt(1 + 25x^2)`
`1/(1 + 5x^2)`
MCQ
रिक्त स्थान भरें
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उत्तर
Let y = `cot^-1((5x^2 + 1)/(4x)) + cot^-1((2x - 3)/(2 + 3x))`, then `dy/dx` = `underline(5/(1 + 25x^2))`.
Explanation:
`y = cot^-1 ((5x . x + 1)/(5x - x)) + cot^-1 ((2/3 x - 1)/(2/3 + x))`
= `tan^-1((5x - x)/(5x . x + 1)) + tan^-1 ((2/3 + x)/(2/3 x - 1))`
= `tan^-1 5x - tan^-1 x + tan^-1 2/3 + tan^-1x`
= `tan^-1 5x + tan^-1 2/3`
∴ `dy/dx = 1/(1 + (5x)^2) . 5 = 5/(1 + 25x^2)`
shaalaa.com
Derivative of Inverse Functions
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