Advertisements
Advertisements
प्रश्न
Let X be a random variable and Y = 2X + 1. What is the variance of Y if variance of X is 5?
Advertisements
उत्तर
Var(X) = 5
Var(Y) = var(2x + 1) .......{∴ v(ax + b) = a2v(x)}
= (2)2var(X)
= 4(5)
Var() = 20
APPEARS IN
संबंधित प्रश्न
Four fair coins are tossed once. Find the probability mass function, mean and variance for a number of heads that occurred
Choose the correct alternative:
If P(X = 0) = 1 – P(X = 1). If E[X] = 3 Var(X), then P(X = 0) is
Let X be a continuous random variable with probability density function
`"f"_x(x) = {{:(2x",", 0 ≤ x ≤ 1),(0",", "otherwise"):}`
Find the expected value of X
State the definition of Mathematical expectation using continuous random variable
The number of miles an automobile tire lasts before it reaches a critical point in tread wear can be represented by a p.d.f.
f(x) = `{{:(1/30 "e"^(- x/30)",", "for" x > 0),(0",", "for" x ≤ 0):}`
Find the expected number of miles (in thousands) a tire would last until it reaches the critical tread wear point
Choose the correct alternative:
Value which is obtained by multiplying possible values of a random variable with a probability of occurrence and is equal to the weighted average is called
Choose the correct alternative:
Demand of products per day for three days are 21, 19, 22 units and their respective probabilities are 0.29, 0.40, 0.35. Profit per unit is 0.50 paisa then expected profits for three days are
Choose the correct alternative:
E[X – E(X)] is equal to
Choose the correct alternative:
E[X – E(X)]2 is
Prove that V(X + b) = V(X)
