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प्रश्न
Let `veca = a_1hati + a_2hatj + a_3hatk a_i > 0`, i = 1, 2, 3 be a vector which makes equal angles with the coordinates axes OX, OY and OZ. Also, let the projection of `veca` on the vector `3hati + 4hatj` be 7. Let `vecb` a vector obtained by rotating `veca` with 90°. If `veca, vecb` and x-axis are coplanar, then projection of a vector `vecb` on `3hati + 4hatj` is equal to ______.
विकल्प
`sqrt(7)`
`sqrt(2)`
2
7
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उत्तर
Let `veca = a_1hati + a_2hatj + a_3hatk a_i > 0`, i = 1, 2, 3 be a vector which makes equal angles with the coordinates axes OX, OY and OZ. Also, let the projection of `veca` on the vector `3hati + 4hatj` be 7. Let `vecb` a vector obtained by rotating `veca` with 90°. If `veca, vecb` and x-axis are coplanar, then projection of a vector `vecb` on `3hati + 4hatj` is equal to `underlinebb(sqrt(2))`.
Explanation:
Given vector is
`veca = a_1hati + a_2hatj + a_3hatk`
When the angle is equal then cos α = `1/sqrt(3)`
`veca = r(1/sqrt(3)hati + 1/sqrt(3)hatj + 1/sqrt(3)hatk) = r/sqrt(3)(hati + hatj + hatk)`
Now projection of `veca` on `vecc` = 7
Here `vecc = 3hati + 4hatj \implies (veca.vecc)/|vecc|` = 7
`r/sqrt(3) ((hati + hatj + hatk).(3hati + 4hatj))/5 = 7 \implies` r = `5sqrt(3)`
Put the value of r in the value of `veca`
`veca = 5(hati + hatj + hatk)`
As `veca, vecb` and x-axis are coplanar then
`vecb = 5λ(hati + hatj + hatk) + μ(hati)`
Take, `veca.vecb = cos90^circ |veca||vecb|`
`\implies` 25λ(3) + 5μ = 0
`\implies` 15λ + μ = 0
`\implies` μ = –15λ
`vecb = 5λ(-2hati + hatj + hatk)`
Take modulus both side
`|vecb| = 5sqrt(3) \implies` λ = `± 1/sqrt(2)`
`vecb = ± 5/sqrt(2)(-2hati + hatj + hatk)`
Projection of `vecb` on `3hati + 4hatj` is
`(vecb.(3hati + 4hatj))/5 = ± 5/sqrt(2)((-6 + 4)/5) = ± sqrt(2)`
