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Integrate the function: 1x+a+x+b

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प्रश्न

Integrate the function:

`1/(sqrt(x+a) + sqrt(x+b))`

योग
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उत्तर

Let I = `int 1/(sqrt(x + a) + sqrt(x + b))`

On multiplying the numerator and denominator by `sqrt(x + a) + sqrt(x + b)`

`= int 1/(sqrt(x + a) + sqrt(x + b)) xx (sqrt(x + a) - sqrt(x + b))/(sqrt(x + a) - sqrt(x + b))`

`= int (sqrt(x + a) - sqrt(x + b))/(sqrt(x + a) - sqrt(x + b))`

`= int (sqrt(x + a) - sqrt(x + b))/(a - b)` dx

`= 1/(a - b) int (x + a)^(1/2) dx - 1/(a - b) int (x + b)^(1/2)` dx

`= 1/(a - b) [2/3 (x + a)^(3/2) - 2/3 (x + b)^(3/2)] + C`

`= 2/(3(a - b))[(x + a)^(3/2) - (x + b)^(3/2)] + C`

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अध्याय 7: Integrals - Exercise 7.12 [पृष्ठ ३५२]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.12 | Q 2 | पृष्ठ ३५२

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