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प्रश्न
Integrate the following with respect to x.
x8(1 + x9)5
योग
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उत्तर
Let f(x) = 1 + x9
Then f'(x) = 9x8
So `int x^8 (1 + x^9)^5 "d"x = 1/9 int 9x^8(1 + x^9)^5 "d"x`
= `1/9 int ["f"(x)]^5 "f'"(x) "d"x`
= `1/9 ["f"(x)]^6/6 + "c"`
= `1/54 (1 + x^9)^6 + "c"`
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