Advertisements
Advertisements
प्रश्न
Integrate the following with respect to x.
`(6x + 7)/sqrt(3x^2 + 7x - 1)`
Advertisements
उत्तर
Let f(x) = 3x2 + 7x – 1
Then f'(x) = 6x + 7
So `int (6x + 7)/sqrt(3x^2 + 7x - 1) "d"x = int ("f'"(x))/("f"(x)) "d"x`
= `2sqrt("f"(x) + "c")`
= `2sqrt(3x^2 + 7x - 1 + "c")`
APPEARS IN
संबंधित प्रश्न
Integrate the following with respect to x.
`1/(sqrt(x + 1) + sqrt(x - 1))`
Integrate the following with respect to x.
`x^3/(x + 2)`
Integrate the following with respect to x.
`("e"^(3x) +"e"^(5x))/("e"^x + "e"^-x)`
Integrate the following with respect to x.
`1/(x(log x)^2`
Integrate the following with respect to x.
sin3x
Integrate the following with respect to x.
`(4x + 2) sqrt(x^2 + x + 1)`
Integrate the following with respect to x.
`1/(2x^2 - 9)`
Choose the correct alternative:
`int ("d"x)/sqrt(x^2 - 36) + "c"`
Evaluate the following integral:
`sqrt(9x^2 + 12x + 3) "d"x`
Evaluate the following integral:
`int log (x - sqrt(x^2 - 1)) "d"x`
