Advertisements
Advertisements
प्रश्न
Integrate the following with respect to x.
2 cos x – 3 sin x + 4 sec2x – 5 cosec2x
Advertisements
उत्तर
`int 2 cos x - 3 sinx + 4 sec^2x - 5 "cosec"^2x`
= `2 int cos x "d"x - 3 int sin x "d"x + 4 int sec^2x - 5 int "cosec"^2 x "d"x`
= 2 sin x + 3 cos x + 4 tan x + 5 cot x + c
APPEARS IN
संबंधित प्रश्न
Integrate the following with respect to x.
`"e"^(2x)/("e"^(2x) - 2)`
Integrate the following with respect to x.
`(6x + 7)/sqrt(3x^2 + 7x - 1)`
Integrate the following with respect to x.
x8(1 + x9)5
Integrate the following with respect to x
`1/(x log x)`
Integrate the following with respect to x.
`1/sqrt(9x^2 - 7)`
Integrate the following with respect to x.
`1/sqrt(x^2 + 6x + 13)`
Choose the correct alternative:
`int "e"^(2x) [2x^2 + 2x] "d"x`
Choose the correct alternative:
`int_2^4 ("d"x)/x` is
Choose the correct alternative:
`int_0^4 (sqrt(x) + 1/sqrt(x)) "d"x` is
Evaluate the following integral:
`int sqrt(2x^2 - 3) "d"x`
