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In the given figure, ∠MNP = 90°, seg NQ ⊥ seg MP, MQ = 9, QP = 4, find NQ. - Geometry Mathematics 2

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प्रश्न

In the given figure, ∠MNP = 90°, seg NQ ⊥ seg MP, MQ = 9, QP = 4, find NQ.

योग
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उत्तर

Given: In ∆MNP,

∠MNP = 90°

NQ ⊥ MP

MQ = 9,

QP = 4

We know that.

In a right-angled triangle, the perpendicular segment to the hypotenuse from the opposite vertex is the geometric mean of the segments into which the hypotenuse is divided.

∴ NQ2 = MQ × QP   ...[Theorem of geometric mean]

∴ NQ2 = 9 × 4

∴ NQ2 = 36

∴ NQ = 6    ...[Taking square root on both side]

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Theorem of Geometric Mean
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Pythagoras Theorem - Practice Set 2.1 [पृष्ठ ३८]

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बालभारती Mathematics 2 [English] Standard 10 Maharashtra State Board
अध्याय 2 Pythagoras Theorem
Practice Set 2.1 | Q 2 | पृष्ठ ३८
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