Advertisements
Advertisements
प्रश्न
In the given figure, HT shows the height of a tree standing vertically. From a point P, the angle of elevation of the top of the tree (that is ∠P) measures 42° and the distance to the tree is 60 metres. Find the height of the tree
Advertisements
उत्तर
Let the height of the tree HT be “x”
In the ΔHTP,
tan 42° = `"HT"/"PT"`
0.9004 = `x/60`
x = 0.9004 × 60
= 54.024
The height of the tree = 54.02 m
APPEARS IN
संबंधित प्रश्न
In the following table, a ratio is given in each column. Find the remaining two ratios in the column and complete the table.
| sin θ | `11/61` | `1/2` | `3/5` | ||||||
| cos θ | `35/37` | `1/sqrt3` | |||||||
| tan θ | `1` | `21/20` | `8/15` | `1/(2sqrt2)` |
Find the value of the following:
sin 49°
Find the value of the following:
tan 54° 26′
Find the value of θ if cos θ = 0.6763
Find the value of θ if tan θ = 0.0720
Find the value of θ if cos θ = 0.0410
Find the value of θ if tan θ = 7.5958
Find the value of the following:
sin 65° 39′ + cos 24° 57’ + tan 10° 10′
Find the value of the following:
tan 70° 17′
The value of 2tan45° – 2sin30° is ______.
