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In the Formation of Electrovalent Compounds, Electrons Are Transferred from One Element to Another. How Are Electrons Involved in the Formation of a Covalent Compound? - Chemistry

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प्रश्न

In the formation of electrovalent compounds, electrons are transferred from one element to another. How are electrons involved in the formation of a covalent compound?

एक पंक्ति में उत्तर
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उत्तर

By mutual sharing of electrons

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अध्याय 4: Atomic Structure and Chemical Bonding - Exercise 4 (E) [पृष्ठ ७७]

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सेलिना Concise Chemistry [English] Class 9 ICSE
अध्याय 4 Atomic Structure and Chemical Bonding
Exercise 4 (E) | Q 18.2 | पृष्ठ ७७

संबंधित प्रश्न

What are covalent compounds?


Give the formula of the compound that would be formed by the combination of the following pair of elements:

 Al and Cl2


Draw the electron-dot structure of H2O compound and state the type of bonding.


A hydrocarbon having one double bond has 100 carbon atoms in its molecule. The number of hydrogen atoms in its molecule will be
(a) 200
(b) 198
(c) 202
(d) 196


Fill in the blank and rewrite the completed statement:
Covalent compounds are generally soluble in _________ solvents.


Define the functional group and complete the following table. 

S.I. No. Functional Group Compound Formula
(1) ______________ _______________

C2H5OH

(2) _______________ _______________ CH3CHO

Write the molecular formula of the given compound.

Acetic acid


Write scientific reason.

Benzene compounds are called aromatic compounds.


Which of the following are correct structural isomers of butane?

  1. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\phantom{....}|\phantom{....}|\\
    \ce{H - C - C - C - C - H}\\
    |\phantom{....}|\phantom{....}|\phantom{....}|\\
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    \end{array}\]

  2. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\phantom{....}|\\
    \ce{H - C - C - C - H}\\
    |\phantom{.....}|\phantom{.....}|\\
    \ce{H}\ce{H-C-H}\ce{H}\\
    |\\
    \ce{H}\\
    \end{array}\]
  3. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\phantom{....}|\\
    \ce{H - C - C - C - H}\\
    |\phantom{.....}\backslash\phantom{..}|\\
    \phantom{....}\ce{H}\phantom{......}\ce{C - H}\phantom{}\\
    \phantom{.......}|\\
    \phantom{.......}\ce{H}\\
    \end{array}\]
  4. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\\
    \ce{H - C - C - H}\\
    |\phantom{....}|\\
    \ce{H - C - C - H}\\
    |\phantom{....}|\\
    \ce{H}\phantom{...}\ce{H}\\
    \end{array}\]

`"CH"_3 - "CH"_2 - "OH" overset("Alkaline""KMnO"_4 + "Heat")(->) "CH"_3 - "COOH"`

In the above given reaction, alkaline KMnO4 acts as 


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