Advertisements
Advertisements
प्रश्न
In the following, find the values of a and b:
`(sqrt(3) - 2)/(sqrt(3) + 2) = "a"sqrt(3) + "b"`
Advertisements
उत्तर
`(sqrt(3) - 2)/(sqrt(3) + 2)`
= `(sqrt(3) - 2)/(sqrt(3) + 2) xx (sqrt(3) - 2)/(sqrt(3 - 2)`
= `(sqrt(3)(sqrt(3) - 2) - 2(sqrt(3) - 2))/((sqrt(3))^2 - (sqrt(2))^2`
= `(3 - 2sqrt(3) - 2sqrt(3) + 4)/(3 - 4)`
= `(7 - 4sqrt(3))/(-1)`
= `-(7 - 4sqrt(3))`
= `-7 + 4sqrt(3)`
= `4sqrt(3) - 7`
= `4sqrt(3) + (-7)`
= `"a"sqrt(3) + "b"`
Hence, a = 4 and b = -7.
APPEARS IN
संबंधित प्रश्न
Simplify :
` 22/[2sqrt3 + 1] + 17/[ 2sqrt3 - 1]`
Simplify by rationalising the denominator in the following.
`(1)/(sqrt(3) + sqrt(2))`
Simplify by rationalising the denominator in the following.
`(sqrt(3) + 1)/(sqrt(3) - 1)`
Simplify by rationalising the denominator in the following.
`(3sqrt(5) + sqrt(7))/(3sqrt(5) - sqrt(7)`
Simplify by rationalising the denominator in the following.
`(sqrt(12) + sqrt(18))/(sqrt(75) - sqrt(50)`
Simplify the following :
`(3sqrt(2))/(sqrt(6) - sqrt(3)) - (4sqrt(3))/(sqrt(6) - sqrt(2)) + (2sqrt(3))/(sqrt(6) + 2)`
If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) + 1)`, find the values of
x3 + y3
Simplify:
`(sqrt(x^2 + y^2) - y)/(x - sqrt(x^2 - y^2)) ÷ (sqrt(x^2 - y^2) + x)/(sqrt(x^2 + y^2) + y)`
Show that: `x^2 + 1/x^2 = 34,` if x = 3 + `2sqrt2`
Show that: `(3sqrt2 - 2sqrt3)/(3sqrt2 + 2sqrt3) + (2 sqrt3)/(sqrt3 - sqrt2) = 11`
