Advertisements
Advertisements
प्रश्न
In the figure, ∠CPD = ∠BPD and AD is the bisector of ∠BAC. Prove that ΔCAP ≅ ΔBAP and CP = BP.
Advertisements
उत्तर
In ΔBAP and ΔCAP
∠BAP = ∠CAP ...(AD is the bisector of ∠BAC)
AP = AP
∠BPD + ∠BPA = ∠CPA + ∠CPA = 180°
∠BPD = ∠CPD
⇒ ∠BPA - ∠CPA
Therefore,
ΔCAP ≅ ΔBAP ...(ASA criteria)
Hence, CP = BP.
APPEARS IN
संबंधित प्रश्न
Mark the correct alternative in each of the following:
If ABC ≅ ΔLKM, then side of ΔLKM equal to side AC of ΔABC is
The following figure shown a triangle ABC in which AB = AC. M is a point on AB and N is a point on AC such that BM = CN.
Prove that:
State, whether the pairs of triangles given in the following figures are congruent or not:
In the figure, RT = TS, ∠1 = 2∠2 and ∠4 = 2∠3. Prove that ΔRBT ≅ ΔSAT.
In the given figure ABCD is a parallelogram, AB is Produced to L and E is a midpoint of BC. Show that:
a. DDCE ≅ DLDE
b. AB = BL
c. DC = `"AL"/(2)`
In the figure, ∠BCD = ∠ADC and ∠ACB =∠BDA. Prove that AD = BC and ∠A = ∠B.
In the figure, AP and BQ are perpendiculars to the line segment AB and AP = BQ. Prove that O is the mid-point of the line segments AB and PQ.
Given that ∆ABC ≅ ∆DEF List all the corresponding congruent sides
It is given that ∆ABC ≅ ∆RPQ. Is it true to say that BC = QR? Why?
Without drawing the triangles write all six pairs of equal measures in the following pairs of congruent triangles.
∆YZX ≅ ∆PQR
