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प्रश्न
In the equilateral ΔABC of side 14 cm, side BC is the diameter of a semicircle as shown in the figure below. Find the area of the shaded region. `("Take" π = 22/7 and sqrt(3) = 1.732)`.
In the equilateral ΔABC of side 14 cm, side BC is the diameter of a semicircle as shown in the adjoining figure. Find the area of the shaded region. `("Take" π = 22/7 and sqrt(3) = 1.732)`.
योग
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उत्तर
Area of shaded part = Area of equilateral ΔABC + Area of semicircle
= `sqrt(3)/4 a^2 + 1/2 πr^2`
Given a = 14 cm and r = `14/2` = 7 cm
∴ Area of shaded part
= `sqrt(3)/4 xx 14^2 + 1/2 xx 22/7 xx 7 xx 7`
= `(1.732 xx 14 xx 14)/4 + 11 xx 7`
= 1.732 × 7 × 7 + 77
= 84.868 + 77
= 161.868 sq. cm.
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