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प्रश्न
In the adjoining figure, AB is the diameter of the circle with centre O. Two tangents p and g are drawn to the circle at points A and B respectively. Prove that p || q. Further, a line CD touches the circle at E and ∠BCD = 110°. Find the measure of ∠ADC.

प्रमेय
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उत्तर

Given that, O is centre of circle and p, q are tangents at point A and B.
As we know, tangent to a circle is perpendicular to the radius at the point of contact.
OB ⊥ q and OA ⊥ p
⇒ ∠OBC = 90° and ∠OAD = 90°
Since, ∠ABC + ∠BAD = 90° + 90°
= 180°
⇒ Tangents p and q are parallel to each other.
∵ CD is tangent as well as transversed line.
∴ By co-interior angles,
∠ADC + ∠BCD = 180°
∠ADC + 110° = 180°
∴ ∠ADC = 70°
Or
∠D = 70°
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