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प्रश्न

In the above figure, a sphere is placed in a cylinder. It touches the top, bottom and curved surface of the cylinder. If the radius of the base of the cylinder is ‘r’, write the answer to the following questions.
- What is the height of the cylinder in terms of ‘r’?
- What is the ratio of the curved surface area of the cylinder and the surface area of the sphere?
- What is the ratio of volumes of the cylinder and of the sphere?
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उत्तर
a. Given: The cylinder has base radius = r and contains a sphere that touches the top, bottom and the curved surface.
The sphere’s radius = cylinder base radius = r. ...(Because it touches the curved surface)
The sphere’s diameter = 2r and since it touches top and bottom, the cylinder height = the sphere’s diameter = 2r.
Height of the cylinder = 2r.
b. Given: Cylinder radius = r and height = 2r (From part a).
Curved surface area (CSA) of cylinder = 2πrh
= 2π × r × (2r)
= 4πr2
Surface area of sphere = 4πR2
= 4πr2
Ratio (CSA of cylinder) : (Surface area of sphere)
= 4πr2 : 4πr2
= 1 : 1
The ratio is 1 : 1 they are equal.
c. Given: Cylinder: radius = r, height = 2r; Sphere: radius = r.
Volume of cylinder = πr2h
= πr2 × 2r
= 2πr3
Volume of sphere = `4/3 πr^3`.
Ratio (cylinder) : (sphere) = `2πr^3 : 4/3 πr^3`
= `2 : 4/3`
= 3 : 2
The ratio of volumes (cylinder : sphere) = 3 : 2 (cylinder is `3/2` times the sphere).
