Question

In previous questions 3 and 4, what is the net power absorbed by each circuit over a complete cycle. Explain your answer.

Answer 1

In the inductive circuit,

rms value of current, I = 15.92 A

rms value of voltage, V = 220 V

Hence, the net power absorbed can be obtained by the relation,

P = VI cos `phi`

Where,

`phi` = Phase difference between V and I

For a pure inductive circuit, the phase difference between alternating voltage and current is 90°, i.e., `phi` = 90°.

Hence, P = 0, i.e., the net power is zero.

In the capacitive circuit,

rms value of current, I = 2.49 A

rms value of voltage, V = 110 V

Hence, the net power absorbed can be obtained as:

P = VI Cos `phi`

For a pure capacitive circuit, the phase difference between alternating voltage and current is 90°, i.e., `phi` = 90°.

Hence, P = 0, i.e., the net power is zero.