Question

In Δ PQR, MN is drawn parallel to QR. If PM = x, MQ = (x-2), PN = (x+2) and NR = (x-1), find the value of x.

Answer 1

In Δ PQR , MN || QR ,

∴ By BPT `"PM"/"MQ" = "PN"/"NR"`

`"x"/("x" - 2) = ("x" + 2)/("x" - 2)`

⇒ x² - x = x² - 4

⇒ - x = - 4

⇒ x = 4