Advertisements
Advertisements
प्रश्न
In how much time will the simple interest on ₹ 3,000 at the rate of 8% per annum be the same as simple interest on ₹ 4,000 at 12% per annum for 4 years?
Advertisements
उत्तर
Let the required number of years be x
Simple Interest I = `"Pnr"/100`
Principal P1 = ₹ 3000
Rate of interest (r) = 8%
Time (n1) = n1 years
Simple Interest I1 = `(3000 xx 8 xx "n"_1)/100` = 240 n1
Principal (P2) = ₹ 4000
Rate of interest (r) = 12%
Time n2 = 4 years
Simple Interest I2 = `(4000 xx 12 xx 4)/100`
I2 = 1920
If I1 = I2
240 n1 = 1920
n1 = `1920/240`
= 8
∴ The required time = 8 years
APPEARS IN
संबंधित प्रश्न
Find the amount to be paid at the end of 3 years in given case:
Principal = ₹ 7,500 at 5% p.a.
Find the interest and the amount on:
₹ 4,000 in `1 1/3` years at 2 paise per rupee per month.
Rohit borrowed Rs. 24,000 at 7.5 percent per year. How much money will he pay at the end of the 4th years to clear his debt?
The interest on a certain sum of money is 0.24 times itself in 3 years. Find the rate of interest.
Anita takes a loan of Rs. 5,000 at 15% per year as the rate of interest. Find the interest she has to pay at the end of one year.
Aravind borrowed a sum of ₹ 8,000 from Akash at 7% per annum. Find the interest and amount to be paid at the end of two years
Given the principal = Rs 40,000, rate of interest = 8% p.a. compounded annually. Find
- Interest if period is one year.
- Principal for 2nd year.
- Interest for 2nd year.
- Amount if period is 2 years.
The ______ of interest on a sum of ₹ 2000 at the rate of 6% per annum for `1 1/2` years and 2 years is ₹ 420.
The simple interest on a sum of ₹ P for T years at R% per annum is given by the formula: Simple Interest = `(T xx P xx R)/100`.
Dhruvika invested money for a period from May 2006 to April 2008 at rate of 12% per annum. If interest received by her is ₹ 1620, find the money invested.
