Question

In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system.

`["Assume "pi=22/7]`

Answer 1

Height (h) of cylindrical pipe = Length of cylindrical pipe = 28 m

Radius (r) of circular end of pipe = (5/2) = 2.5 cm = 0.025 m

CSA of cylindrical pipe = 2πrh

`=(2xx22/7xx0.025xx28)m^2`

= 4.4m²

The area of the radiating surface of the system is 4.4 m².