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In Following Cases, Determine the Direction Cosines of the Normal to the Plane and the Distance from the Origin.X + Y + Z = 1 - Mathematics

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प्रश्न

In following cases, determine the direction cosines of the normal to the plane and the distance from the origin.

x + y + z = 1

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उत्तर

x + y + z = 1 … (1)

The direction ratios of normal are 1, 1, and 1.

This equation is of the form lx + my + nz = d, where lmn are the direction cosines of normal to the plane and d is the distance of normal from the origin.

Therefore, the direction cosines of the normal are `1/sqrt3, 1/sqrt3 and 1/sqrt3` the distance of normal from the origin is `1/sqrt3` units.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Three Dimensional Geometry - Exercise 11.3 [पृष्ठ ४९३]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 11 Three Dimensional Geometry
Exercise 11.3 | Q 1.2 | पृष्ठ ४९३

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