Question

In figure, PQ is parallel to BC, AP : AB = 2 : 7. If QC = 0 and BC = 21,

Find
(i) AQ
(ii) PQ

Answer 1

(i) Since PQ || BC

`"AP"/"PB" = "AQ"/"QC"`

⇒ `"AP"/("AB" - "AP") = "AQ"/"QC"`

⇒ `(2)/(5) = "AQ"/(10)`

⇒ AQ = `(2 xx 10)/(5)`
⇒ AQ = 4.
(ii) Since PQ || BC

`"AP"/"AB" = "PQ"/"BC"`

⇒ `(2)/(7) = "PQ"/(21)`

⇒ PQ = `(2 xx 21)/(7)`
⇒ PQ = 6.