Advertisements
Advertisements
प्रश्न
In each of the following, find the value of the constant k so that the given function is continuous at the indicated point; \[f\left( x \right) = \binom{\frac{x^3 + x^2 - 16x + 20}{\left( x - 2 \right)^2}, x \neq 2}{k, x = 2}\]
योग
Advertisements
उत्तर
Given:
\[f\left( x \right) = \binom{\frac{x^3 + x^2 - 16x + 20}{\left( x - 2 \right)^2}, x \neq 2}{k, x = 2}\]
\[\Rightarrow f\left( x \right) = \binom{\frac{x^3 + x^2 - 16x + 20}{x^2 - 4x + 4}, x \neq 2}{k, x = 2}\]
\[\Rightarrow f\left( x \right) = \binom{x + 5, x \neq 2}{k, x = 2}\]
If f(x) is continuous at x = 2, then
\[\lim_{x \to 2} f\left( x \right) = f\left( 2 \right)\]
\[ \Rightarrow \lim_{x \to 2} \left( x + 5 \right) = k\]
\[ \Rightarrow k = 2 + 5 = 7\]
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
