हिंदी

In each of the following, find the value of the constant k so that the given function is continuous at the indicated point; f ( x ) = { k x + 1 , if x ≤ π cos x , if x > π at x = π - Mathematics

Advertisements
Advertisements

प्रश्न

In each of the following, find the value of the constant k so that the given function is continuous at the indicated point; 

\[f\left( x \right) = \begin{cases}kx + 1, \text{ if }  & x \leq \pi \\ \cos x, \text{ if }  & x > \pi\end{cases}\] at x = π
योग
Advertisements

उत्तर

\[f\left( x \right) = \begin{cases}kx + 1, \text{ if }  & x \leq \pi \\ \cos x, \text{ if }  & x > \pi\end{cases}\] 
We have
(LHL at x =  \[\pi\] = \[\lim_{x \to \pi^-} f\left( x \right) = \lim_{h \to 0} f\left( \pi - h \right) = \lim_{h \to 0} k\left( \pi - h \right) + 1 = k\pi + 1\]
\[\pi\]= \[\lim_{x \to \pi^+} f\left( x \right) = \lim_{h \to 0} f\left( \pi + h \right) = \lim_{h \to 0} \cos\left( \pi + h \right) = cos\pi = - 1\]
If f(x) is continuous at x = 
\[\pi\] , then
\[\lim_{x \to \pi^-} f\left( x \right) = \lim_{x \to \pi^+} f\left( x \right)\]

\[\Rightarrow k\pi + 1 = - 1\]
\[ \Rightarrow k = \frac{- 2}{\pi}\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Continuity - Exercise 9.1 [पृष्ठ २०]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
अध्याय 9 Continuity
Exercise 9.1 | Q 36.4 | पृष्ठ २०
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×