Question

In an electrical circuit two resistors of 2 Ω and 4 Ω respectively are connected in series to a 6 V battery. The heat dissipated by the 4 Ω resistor in 5 s will be

विकल्प

• 5J

• 10J

• 20J

• 30J

Answer 1

20J

Explanation -

Since 2Ω and 4Ω are connected in series so their net resistance is 

`"R"_"net" = "R"_1 + "R"_2`

`"R"_"net" = 2 + 4`

R_net = 6Ω

Current (I) in the circuit is given by 

`"I" = "V"/("R"_1 + "R"_2)`

`"I" = 6/6`

I = 1A

Heat dissipated through 4Ω resistor is given by 

H = I² × R × t

H = I² × 4 × 5

H = 20J