Question

In a two-digit number, the digit at the ten's place is 4 times the digit at the unit's place.The sum of the digits and the number is 92. Find the two digit number.

Answer 1

Let the units place be x and tens place be y.
Then, the two-digit number is 10y + x.
Given, the digit at the ten's place is 4 times the digit at the unit's place.
⇒ y = 4x ---(1)
Also, sum of the digits and the number is 92.
⇒ x + y + (10y + x) = 92
⇒ 11y + 2x = 92----(2)
Solving (1) and (2), we get:
11 x 4x + 2x = 92
46x = 92
⇒ x = 2
So, y = 8
Then, the two-digit number is 10 x 8 + 2 = 82..