Question

In a reaction, \[\ce{A -> B}\], the rate of reaction increases two times on increasing the concentration of reactants four times. The order of reaction is ______.

विकल्प

• 0

• 2

• `1/2`

• 4

Answer 1

In a reaction, \[\ce{A -> B}\], the rate of reaction increases two times on increasing the concentration of reactants four times. The order of reaction is `bbunderline(1/2)`.

Explanation:

For the reaction:

\[\ce{A -> B}\]

Rate increases 2 times

Concentration increases 4 times

We use the rate law:

Rate ∝ [A]ⁿ

Then,

\[\ce{\frac{Rate_2}{Rate_1} = (\frac{[A]_2}{[A]_1})^n}\]

⇒ 2 = 4ⁿ = (2²)ⁿ = 2²ⁿ

⇒ 2 = 2²ⁿ

⇒ 2ⁿ = 1

⇒ `n = 1/2`