Advertisements
Advertisements
प्रश्न
In a cell that utilises the reaction \[\ce{Zn_{(s)} + 2H{^{+}_{(aq)}} -> Zn{^{2+}_{(aq)}} + H2_{(g)}}\] addition of H2SO4 to cathode compartment will ______.
विकल्प
lower the E and shift equilibrium to the left.
lower the E and shift the equilibrium to the right.
increase the E and shift the equilibrium to the right.
increase the E and shift the equilibrium to the left.
Advertisements
उत्तर
In a cell that utilises the reaction \[\ce{Zn_{(s)} + 2H{^{+}_{(aq)}} -> Zn{^{2+}_{(aq)}} + H2_{(g)}}\] addition of H2SO4 to cathode compartment will increase the E and shift the equilibrium to the right.
Explanation:
\[\ce{Zn_{(s)} + 2H{^{+}_{(aq)}} -> Zn{^{2+}_{(aq)}} + H2_{(g)}}\]
The corresponding cell is:
\[\ce{E_{cell} = E{^{\circ}_{cell}} - \frac{0.0591}{n} log_10 \frac{[Zn^{2+} [pH_2]}{[H^{+}]^2}}\]
The addition of H2SO4 increases [H+]. This increases the value of Ecell and shifts the equilibrium to the right, as per Le Chatelier’s principle.
