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In a business venture a man can make a profit of ₹ 2,000 with a probability of 0.4 or have a loss of ₹ 1,000 with a probability of 0.6. What is his expected, variance and standard deviation of profit? - Business Mathematics and Statistics

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प्रश्न

In a business venture a man can make a profit of ₹ 2,000 with a probability of 0.4 or have a loss of ₹ 1,000 with a probability of 0.6. What is his expected, variance and standard deviation of profit?

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उत्तर

Let X be the random variable of getting profit in a business

X 2000 – 1000
P(X = x) 0.4 0.6

E(x) = Σxxpx(x)

= (0.4 × 2000) + [0.6 × (– 1000)]

= 800 – 600

E(X) = 200

∴ Expected value of profit = ₹ 200

E(X2) = Σx2 Px(x)

= [(2000)2 × 0.4] + [(– 1000)2 × 0.6]

= (4000000 × 0.4) + (1000000 × 0.6)

E(X2) = 2200000

Var(X) = E(X2) – [E(X)]2

= 22000000 – (200)2

= 2200000 – 40000

Var(X) = 21,60,000

Variance of his profit = ₹ 21,60,000

Standard deviation(S.D) = `sqrt("Var"(x))`

σ = `sqrt(2160000)`

σ = 1469.69

Standard deviation of his profit is ₹ 1,469.69

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Mathematical Expectation
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Random Variable and Mathematical expectation - Exercise 6.2 [पृष्ठ १४१]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 6 Random Variable and Mathematical expectation
Exercise 6.2 | Q 12 | पृष्ठ १४१

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