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If Y = X Sin Y , Prove that D Y D X = Y X ( 1 − X Cos Y ) ? - Mathematics

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प्रश्न

If \[y = x \sin y\] , prove that  \[\frac{dy}{dx} = \frac{y}{x \left( 1 - x \cos y \right)}\] ?

 

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उत्तर

\[\text{ We have }, y = x \sin y . . . \left( i \right)\]
Differentiating with respect to x,
\[\frac{dy}{dx} = \frac{d}{dx}\left( x \sin y \right)\]
\[ \Rightarrow \frac{dy}{dx} = x\frac{d}{dx}\left( \sin y \right) + \sin y\frac{d}{dx}\left( x \right) \]
\[ \Rightarrow \frac{dy}{dx} = x \cos y\frac{dy}{dx} + \sin y\left( 1 \right)\]
\[ \Rightarrow \frac{dy}{dx} - x \cos y\frac{dy}{dx} = \sin y\]
\[ \Rightarrow \frac{dy}{dx}\left( 1 - x \cos y \right) = \sin y\]
\[ \Rightarrow \frac{dy}{dx} = \frac{\sin y}{\left( 1 - x \cos y \right)}\]
\[ \Rightarrow \frac{dy}{dx} = \frac{y}{x\left( 1 - x \cos y \right)} \left[ \because \sin y = \frac{y}{x} \right]\]
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अध्याय 11: Differentiation - Exercise 11.05 [पृष्ठ ९०]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 11 Differentiation
Exercise 11.05 | Q 50 | पृष्ठ ९०

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