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If y = tan-1(2x1-x2), x ∈ (−1, 1) then dddydx = ______. - Mathematics and Statistics

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प्रश्न

If y = `tan^-1((2x)/(1 - x^2))`, x ∈ (−1, 1) then `("d"y)/("d"x)` = ______.

विकल्प

  • `(-2)/(1 + x^2)`

  • 1

  • `(2)/(1 + x^2)`

  • `1/(1 + x^2)`

MCQ
रिक्त स्थान भरें
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उत्तर

If y = `tan^-1((2x)/(1 - x^2))`, x ∈ (−1, 1) then `("d"y)/("d"x)` = `bbunderline((2)/(1 + x^2))`.

Explanation:

Put x = tan θ, `(-pi)/4 < theta < pi/4`

∴ tan−1 x

`therefore y = tan^-1 ((2 tan theta)/(1 - tan^2theta))`

∴ y = tan−1 (tan 2 θ)

∴ y = 20 

∴ y = 2 tan−1 x

`therefore dy/dx = 2/(1 + x^2)`

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Derivatives of Inverse Functions
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अध्याय 2.1: Differentiation - MCQ

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