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प्रश्न
If y = sin-1 x + cos-1x find `(dy)/(dx)`.
योग
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उत्तर
y = `sin^-1 x + cos^-1 x`
⇒`(dy)/(dx )= d/(dx) (sin^-1 x + cos^-1 x )`
= `d/(dx) (sin^-1 x) + d/(dx) (cos^-1 x)`
= `1/sqrt(1-x^2) - 1/sqrt(1-x^2)`
= 0
Therefore, `(dy)/(dx)` = 0.
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