Advertisements
Advertisements
प्रश्न
If y = 2 sin x + 3 cos x, then show that y2 + y = 0.
Advertisements
उत्तर
Given y = 2 sin x + 3 cos x ....(1)
Differentiating with respect to 'x' we get,
y1 = 2 cos x - 3 sin x
Differentiating again with respect to 'x' we get,
y2 = 2 (- sin x) - 3 cos x
y2 = - 2 sin x - 3 cos x ....(2)
Adding (1) and (2) we get,
y + y2 = 2 sin x + 3 cos x - 2 sin x - 3 cos x
= 0
y + y2 = 0
Hence proved.
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
3x4 – 2x3 + x + 8
Differentiate the following with respect to x.
sin x cos x
Differentiate the following with respect to x.
cos3 x
Differentiate the following with respect to x.
`sqrt(1 + x^2)`
Differentiate the following with respect to x.
(ax2 + bx + c)n
Differentiate the following with respect to x.
`1/sqrt(1 + x^2)`
Find `"dy"/"dx"` for the following function
xy – tan(xy)
If 4x + 3y = log(4x – 3y), then find `"dy"/"dx"`
Differentiate the following with respect to x.
(sin x)tan x
If y = 500e7x + 600e-7x, then show that y2 – 49y = 0.
