Advertisements
Advertisements
प्रश्न
If y = 2 sin x + 3 cos x, then show that y2 + y = 0.
Advertisements
उत्तर
Given y = 2 sin x + 3 cos x ....(1)
Differentiating with respect to 'x' we get,
y1 = 2 cos x - 3 sin x
Differentiating again with respect to 'x' we get,
y2 = 2 (- sin x) - 3 cos x
y2 = - 2 sin x - 3 cos x ....(2)
Adding (1) and (2) we get,
y + y2 = 2 sin x + 3 cos x - 2 sin x - 3 cos x
= 0
y + y2 = 0
Hence proved.
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
3x4 – 2x3 + x + 8
Differentiate the following with respect to x.
ex sin x
Differentiate the following with respect to x.
x3 ex
Find `"dy"/"dx"` for the following function.
x2 – xy + y2 = 1
Find `"dy"/"dx"` for the following function.
x3 + y3 + 3axy = 1
Find `"dy"/"dx"` of the following function:
x = a(θ – sin θ), y = a(1 – cos θ)
Find y2 for the following function:
y = log x + ax
If y = 500e7x + 600e-7x, then show that y2 – 49y = 0.
If y = sin(log x), then show that x2y2 + xy1 + y = 0.
If xy2 = 1, then prove that `2 "dy"/"dx" + y^3`= 0
