Advertisements
Advertisements
प्रश्न
If y = 2 + log x, then show that xy2 + y1 = 0.
योग
Advertisements
उत्तर
y = 2 + log x
`y_1 = 0 +1/x`
i.e., `y_1 = 1/x`
`therefore y_2 = - 1/x^2`
Now `xy_2 + y_1 = x(- 1/x^2) + 1/x = (-1)/x + 1/x = 0`
shaalaa.com
Differentiation Techniques
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
`5/x^4 - 2/x^3 + 5/x`
Differentiate the following with respect to x.
x sin x
Differentiate the following with respect to x.
sin x cos x
Differentiate the following with respect to x.
sin(x2)
Differentiate the following with respect to x.
`1/sqrt(1 + x^2)`
Differentiate the following with respect to x.
`sqrt(((x - 1)(x - 2))/((x - 3)(x^2 + x + 1)))`
If xm . yn = (x + y)m+n, then show that `"dy"/"dx" = y/x`
Differentiate sin2x with respect to x2.
If = a cos mx + b sin mx, then show that y2 + m2y = 0.
If y = tan x, then prove that y2 - 2yy1 = 0.
