Question

If `x^2 + 1 = 2x`, then find `x - (1/x)`

विकल्प

• 0

• 2

• 4

• 12

Answer 1

0

Explanation:

`x^2 + 1 = 2x`

⇒ `x^2 - 2x + 1` = 0

⇒ `x^2 - x - x + 1` = 0

⇒ `x(x - 1) + 1(x - 1)` = 0

⇒ `(x - 1)(x + 1)` = 0

So, `x = 1, -1`

Putting `x = 1`

`x - 1/x = 1 - 1/1 = 1 - 1` = 0

Putting `x = (-1)`

`x - 1/x = (-1) - 1/(-1) = - 1 + 1` = 0