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If X = a Cos Nt − B Sin Nt and D 2 X D T = λ X Then Find the Value of λ ? - Mathematics

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प्रश्न

If x = a cos nt − b sin nt and \[\frac{d^2 x}{dt} = \lambda x\]  then find the value of λ ?

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उत्तर

Here,

\[x = a \cos nt - b \sin nt\]

\[\text { Now,} \]

\[\frac{d x}{d t} = - an \sin nt - bn \cos nt\]

\[ \frac{d^2 x}{d t^2} = - a n^2 \cos nt + b n^2 \sin nt\]

\[\text { Also}, \]

\[\frac{d^2 x}{d t^2} = \lambda x \left[ \text { Given } \right]\]

\[ \Rightarrow - a n^2 \cos nt + b n^2 \sin nt = \lambda\left( a \cos nt - b \sin nt \right)\]

\[ \Rightarrow - n^2 \left( a \cos nt - b \sin nt \right) = \lambda\left( a \cos nt - b \sin nt \right)\]

\[ \Rightarrow \lambda = - n^2\]

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अध्याय 12: Higher Order Derivatives - Exercise 12.2 [पृष्ठ २२]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 12 Higher Order Derivatives
Exercise 12.2 | Q 2 | पृष्ठ २२

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