Advertisements
Advertisements
प्रश्न
If x = `1/10` and y = `(-3)/8`, then evaluate x + y, x – y, x × y and x ÷ y.
Advertisements
उत्तर
Given, x = `1/10` and y = `(-3)/8`
Now, x + y = `1/10 + ((-3))/8`
= `1/10 - 3/8`
= `(1 xx 4)/(10 xx 4) - (3 xx 5)/(8 xx 5)` ...[∵ LCM of 10 and 8 = 40]
= `4/40 - 15/40`
= `(4 - 15)/40`
= `-11/40`
And x – y = `1/10 - (-3/8)`
= `1/10 + 3/8`
= `(1 xx 4)/(10 xx 4) + (3 xx 5)/(8 xx 5)` ...[∵ LCM of 10 and 8 = 40]
= `4/40 + 15/40`
= `(4 + 15)/40`
= `19/40`
∴ Product of rational numbers = `"Product of numerators"/"Product of denominators"`
⇒ x × y = `1/10 xx ((-3))/8`
= `(1 xx (-3))/(10 xx 8)`
= `(-3)/80`
And x ÷ y = `1/10 ÷ ((-3)/8)`
The reciprocal of `((-3)/8)` is `8/(-3)`
So, x ÷ y = `1/10 xx 8/(-3)`
= `(1 xx 8)/(10 xx - 3)`
= `(-8)/30`
= `(-8 ÷ 2)/(30 ÷ 2)` ...[Dividing numerator and denominator by 2]
= `(-4)/15`
APPEARS IN
संबंधित प्रश्न
Find the value of `(-3)/5 ÷ 2`.
Evaluate:
`- 5/12 ÷ 1/16`
Evaluate:
`3/4 ÷ (-5/12)`
Divide:
`(-5)/8 "by" 1/4`
Find (m + n) ÷ (m - n), if:
m = `4/5` and n = `-3/10`
Divide : −2 by `(-6)/(15)`
If `p/q` is a rational number and m is a non-zero common divisor of p and q, then `p/q = (p ÷ m)/(q ÷ m)`.
Match the following:
| Column I | Column II |
| (i) `a/b ÷ a/b` | (a) `(-a)/b` |
| (ii) `a/b ÷ c/d` | (b) –1 |
| (iii) `a/b ÷ (-1)` | (c) 1 |
| (iv) `a/b ÷ (-a)/b` | (d) `(bc)/(ad)` |
| (v) `b/a ÷ (d/c)` | (e) `(ad)/(bc)` |
Reduce the following rational numbers in its lowest form:
`(-60)/72`
Taking x = `(-4)/9`, y = `5/12` and z = `7/18`, find x ÷ (y ÷ z).
