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प्रश्न
If the plot of log10 [A] against t is a straight line with a negative slope, the reaction is of ______.
विकल्प
zero order
first order
second order
third order
MCQ
रिक्त स्थान भरें
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उत्तर
If the plot of log10 [A] against t is a straight line with a negative slope, the reaction is of first order.
Explanation:
For a first-order reaction, the integrated rate law is:
log10 [A] = `log_10 [A]_0 - k/2.303 t`
This is a straight-line equation with a negative slope when plotting log10 [A] vs t. The negative slope confirms first-order kinetics.
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