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If the heights of 500 students are normally distributed with mean 68.0 inches and standard deviation 3.0 inches , how many students have height greater than 72 inches

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प्रश्न

If the heights of 500 students are normally distributed with mean 68.0 inches and standard deviation 3.0 inches, how many students have height greater than 72 inches

योग
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उत्तर

Let x denote the height of a student N = 500; m = 68.0 inches and σ = 3.0 inches the standard normal variate

z = `(x - mu)/sigma = (x - 68)/3`

P(Greater than 72 inches)

P = P(X > 72)

When x = 72

z = `(72 - 68)/3 = 4/3` = 1.33

P(x > 72) = P(z > 1.33)

= 0.5 – 0.4082

= 0.0918

Number of students whose height are greater than 72 inches

= 0.0918 × 500

= 45.9

= 46  ......(approximately)

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अध्याय 7: Probability Distributions - Exercise 7.3 [पृष्ठ १६८]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 7 Probability Distributions
Exercise 7.3 | Q 8. (a) | पृष्ठ १६८

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