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प्रश्न
If sin x = `7/25`, where x is an acute angle, then find the value of sin x ⋅ cos x (tan x + cot x).
योग
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उत्तर
sin x ⋅ cos x (tan x + cot x)
= `sin x ⋅ cos x(sin x/cos x + cos x/sin x)`
= `sin x ⋅ cos x ((sin^2x + cos^2x)/(cos x ⋅ sin x))`
= `sin x ⋅ cos x(1/(cos x ⋅ sin x))`
= 1 (Constant)
Since the value of sin x ⋅ cos x (tan x + cot x) is constant, it is equal to 1 for all angles.
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