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प्रश्न
If planes `vecr.(phati - hatj + 2hatk) + 3` = 0 and `vecr.(2hati - phatj - hatk) - 5` = 0 include angle `π/3` then the value of p is ______.
विकल्प
1, –3
–1, –3
–3
3
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उत्तर
If planes `vecr.(phati - hatj + 2hatk) + 3` = 0 and `vecr.(2hati - phatj - hatk) - 5` = 0 include angle `π/3` then the value of p is 3.
Explanation:
We have `vecr.(phati - hatj + 2hatk) + 3` = 0 and `vecr.(2hati - phatj - hatk) - 5` = 0
Since the angle between them is `π/3`
∴ cos θ = `|(vecn_1.vecn_2)/(|vecn_1|.|vecn_2|)|`
`\implies cos π/3 ((phati - hatj + 2hatk).(2hati - phatj - hatk))/(sqrt((p)^2 + (-1)^2 + (2)^2) sqrt((2)^2 + (-p)^2 + (-1)^2`
`\implies 1/2 = (2p + p - 2)/((sqrt(p^2 + 5))(sqrt(p^2 + 5))`
`\implies 1/2 = (3p - 2)/((p^2 + 5))`
`\implies` p2 + 5 = 6p – 4
`\implies` p2 – 6p + 9 = 0
`\implies` (p – 3)2 = 0
`\implies` p = 3
