Question

If p = −2, q = 1 and r = 3, find the value of 3p²q²r

Answer 1

Given p = −2, q = 1, r = 3

∴ 3p²q²r = 3 × (−2)² × (1)² × (3)

= 3 × (−2 × 1)² × (3)  ...[Since a^m × b^m = (a × b)^m]

= 3 × (−2)² × (3)

= 3 × (−1)² × 2² × 3

= 3¹⁺¹ × 1 × 4  ...[Since a^m × aⁿ = a^m+n]

= 3² × 4

= 9 × 4

∴ 3p²q²r = 36