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प्रश्न
If P = `[(1,-1,0),(2,3,4),(0,1,2)]` and Q = `[(2,2,-4),(-4,2,-4),(2,-1,5)]` find (QP) and hence solve the following system of equations using matrices:
x – y = 3, 2x + 3y + 4z = 17, y + 2z = 7
योग
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उत्तर
Given,
QP = `[(1,-1,0),(2,3,4),(0,1,2)] [(2,2,-4),(-4,2,-4),(2,-1,5)]`
= `[(6,0,0),(0,6,0),(0,0,6)]`
= `6[(1,0,0),(0,1,0),(0,0,1)]`
= 6I
By the system of equations:
A = `[(1,-1,0),(2,3,4),(0,1,2)];X=[(x),(y),(z)];B=[(3),(17),(7)]`
AX = B
X = A–1B
QA = 6I
Post multipication of A–1 both sides,
QAA–1 = 6IA–1 ...[∵ AA–1 = I]
Q = 6A–1
A–1 = `1/6`Q
X = A–1B
= `1/6`QB
A–1 = `1/6[(2,2,-4),(-4,2,-4),(2,-1,5)][(3),(17),(7)]`
X = `1/6[(6+34-28),(-12+34-28),(6-3+35)]`
X = `1/6[(12),(-6),(24)]`
`[(x),(y),(z)]=[(2),(-1),(4)]`
Hence, x = 2, y = –1, z = 4
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