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प्रश्न
If `lim_(x rightarrow 1) (x^4 - 1)/(x - 1)` = `lim_(x rightarrow k) (x^3 - k^3)/(x^2 - k^2)`, then k is ______.
विकल्प
`8/3`
`3/8`
`3/2`
`4/3`
MCQ
रिक्त स्थान भरें
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उत्तर
If `lim_(x rightarrow 1) (x^4 - 1)/(x - 1)` = `lim_(x rightarrow k) (x^3 - k^3)/(x^2 - k^2)`, then k is `underlinebb(8/3)`.
Explanation:
Given, `lim_(x rightarrow 1) (x^4 - 1)/(x - 1)` = `lim_(x rightarrow k) ((x^3 - k^3)/(x^2 - k^2))`
Taking L.H.S. `lim_(x rightarrow 1) (x^4 - 1)/(x - 1)` ...`(0/0 "form")`
`lim_(x rightarrow 1) (4x^3)/1` = 4 ...[Using L Hospital's Rule]
∴ `lim_(x rightarrow k) (x^3 - k^3)/(x^2 - k^2)` = 4
⇒ `lim_(x rightarrow k) (3x^2)/(2x)` = 4 ...[Using L Hospital's Rule]
⇒ `3/2k` = 4
⇒ k = `8/3`
shaalaa.com
Limits Using L-hospital's Rule
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